Question

What shall be the percentage of increase in the surface area of a cube when each side is
doubled?​

Answer 1

Answer:300%

Step-by-step explanation:

A cube has 6 sides,

old surface area = 6xa^2 where "a" is the length of each side.

when side is doubled, A=2a

new surface area= 6xA^2 = 6x(2a)^2 = 6x4a^2 = 4x(old surface area)

% change in area is = {(new area - old area ) / (old area)} x 100%

= {(4(6a^2) - 6a^2)/6a^2 } x 100 %

= 3x100%

=300%

since new area is larger than the old area, we say there is an increase of 300%