Question

what shoud be added to 7 3/4 to get 18​

Answer 1

Let the required number be x.

According to question:

$7 \frac{3}{4} + x = 18 \\ \\ (4 \times 7) +3 = \\ \\ \frac{31}{4} + x = 18 \\ \\ x = 18 - \frac{31}{4} \\ \\ x = (18 \times 4) - 31 \div 4 \\ \\ x = \frac{72 - 31}{4} \\ \\ x = \frac{41}{4} = 10\times \frac{1}{4} = 10 \frac{1}{4}$

Thus, the required no. is

$10 \frac{1}{4}$

Answer 2

Sum=18

One of the Number

$= 7 \frac{3}{4} \\ \\ \frac{7 \times 4 + 3}{4} \\ \\ \frac{31}{4}$

Let Other Number=x

A/Q

$\frac{31}{4} + x = 18 \\ \\ x = 18 - \frac{31}{4} \\ \\ x = \frac{18 \times 4 - 31}{4} \\ \\ x = \frac{72 - 31}{4} \\ \\ x = \frac{41}{4} \\ \\ other \: number = \frac{41}{4}$

So

41/4 should be added to 31/4 to get=18