Question

What should be add to 4pq-4q-6r to get 3pq+2q-12

Answer 1

Answer:

(i) 4, 7p

Answer: 4×7p=28p4×7p=28p

(ii) – 4p, 7p

Answer: −4p×7p=−28p2-4p×7p=-28p2

(iii) – 4p, 7pq

Answer: −4p×7pq=−28p2q-4p×7pq=-28p2q

(iv) 4p34p3, – 3p

Answer: 4p3q×−3p=−12p4q4p3q×-3p=-12p4q

(v) 4p, 0

Answer: 4p×0=0

Step-by-step explanation:

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Answer 2

Answer:

-pq +6q- 6r

4pq-4q-6r+(-pq+6q-6r)

=4pq-4q-6r-pq+6q-6r

=3pq+2q-12r

i think this would be the answer