what should be added 3x³+4x²-7 to get 5x³+6x⁴-11
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Answer:
Let the polynomial to be added be y
A/Q
3x³+4x²-7 + y = 5x³+6x⁴-11
y= 5x³+6x⁴-11 -(3x³+4x²-7)
y= 5x³+6x⁴-11-3x³-4x²+7
y= 2x³+6x⁴-4-4x² (solving the like terms)
Therefore,
2x³+6x⁴-4x²-4 must be added to 3x³+4x²-7 to get 5x³+6x⁴-11
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