Question

what should be added to (1/2+1/3-1/5)to get 3 ?

Answer 1

Your answer....
(1/2+1/3-1/5)
=15+10+6/30 (taking 30 as common denominator)
=19/30
Next step:
3- 19/30=90-19/30 =71/30=2(11/30)
Hope this helps

Answer 2

$If \ 2.37 \ is \ added \ to \left(\frac{1}{2}+\frac{1}{3}-\frac{1}{5}\right), we \ will \ get \ 3$

Given:

$\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{5}\right)$

Solution:

Common denominator should be present in order to add the fractions. The numbers in the bottom must be same. “Least common multiple” of 3, 2, and 5 is 30.

Since, 3, 2, and 5 are all prime numbers.

The L.C.M is,

$3 \times 2 \times 5=30$

Now, the bottom of the answer should be 30, just by multiplying unit fractions.

So, the solution derivation will be,

In that the added number will be considered as x

$\frac{1}{2}+\frac{1}{3}-\frac{1}{5}+x=3$

$\Rightarrow\left(\left(\frac{1}{3}\right) \times\left(\frac{10}{10}\right)\right)+\left(\left(\frac{1}{2}\right) \times\left(\frac{15}{15}\right)\right)-\left(\left(\frac{1}{5}\right) \times\left(\frac{6}{6}\right)\right)+\left(\frac{30 x}{30}\right)=3$

$\Rightarrow \frac{10}{30}+\frac{15}{30}-\frac{6}{30}+\frac{30 x}{30}=3$

$\Rightarrow \frac{19+30 x}{30}=3$

$\Rightarrow 19+30 x=3 \times 30$

$\Rightarrow 30 x=90-19$

$\Rightarrow x=\frac{71}{30}$

$x=2.37$