Question

what should be added to (1/-2 - 3/4 of -8/5) so that the sum is the product of -7/50 and 1 1/4.​

Answer 1

✧$\huge \mathcal \red {\underline{\underline{A}}}$ $\huge \mathcal \green {\underline{\underline{N}}}$ $\huge \mathcal \pink {\underline{\underline{S}}}$ $\huge \mathcal \blue {\underline{\underline{W}}}$ $\huge \mathcal \orange {\underline{\underline {E}}}$ $\huge \mathcal \purple {\underline{\underline{R}}}$✧

❥︎ Given :

What should be added to ( $\frac {1}{-2} - \frac {3}{4} \: of \: \frac {-8}{5}$ ) so that the sum is the product of $\frac {-7}{50} \: and \: 1 \frac {1}{4}$?

❥︎ To find :

The number

❥︎ Solution :

Let the number be x.

→ x + $\frac {1}{-2} - \frac {3}{4} × \frac {-8}{5}$ = $\frac {-7}{50} × 1 \frac{1}{4}$

→ x - $\frac {1}{2} - \frac {-6}{5}$ = $\frac {-7}{50} × {5}{4}$

→ x - $\frac {1}{2} + \frac {6}{5} = \frac {-7}{40}$

→ x + $\frac {7}{10} = \frac {-7}{40}$

→ x = $\frac {-7}{40} - \frac {7}{10}$

→ x = $\frac {-35}{40}$

→ x = $\frac {-7}{8}$

$\therefore$ Hence, $\frac {-7}{8}$ should be added to ( $\frac {1}{-2} - \frac {3}{4} \: of \: \frac {-8}{5}$ ) so that the sum is the product of $\frac {-7}{50} \: and \: 1 \frac{1}{4}.$

____________________☆