Question

what should be added to 10, 18, 22, 38, so that they become proportional​

Answer 1

Answer:

Step-by-step explanation:

If a : b = c : d are in proportion then a/b = c/d

i.e. ad = bc

Product of extremes = Product of means

Let the no: be 'x'

(10+x) : (18+x) : (22+x) : (38+x)

(10+x)(38+x) = (18+x)(22+x)

380 + 10x + 38x + x² = 396 + 18x + 22x + x²

380 + 48x + x² = 396 + 40x + x²

396 - 380 + 40x - 48x = 0

16 - 8x = 0

-8x = - 16

x = 2

$\boxed{x = 2}$

2 should be added to each terms ( 10 , 18 , 22 , 38 ) so that they become Proportional

New proportion = 12 , 20 , 24 , 40

12 × 40 = 20 × 24

480 = 480