Question

What should be added to 2.x2 + xy + 2y2 to obtain 3x2 + 5xy? ​

Answer 1

Answer:

k = x² + 4xy - 2y²

Step-by-step explanation:

let the number = k

2x² + xy +2y² + k = 3x² + 5xy

2x² + xy +2y² + k = 3x² + 5xy k = 3x² + 5xy - ( 2x² + xy + 2y² )

2x² + xy +2y² + k = 3x² + 5xy k = 3x² + 5xy - ( 2x² + xy + 2y² )k = 3x²+ 5xy -2x²-xy - 2y²

k = x² + 4xy - 2y²

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Answer 2

Answer:

Ans. x^2-2y^2+4xy.

Step-by-step explanation:

Sol. Let the no. be = k.

Therefore, according to question

2x^2+xy+2y^2+k = 3x^2+5xy

=> 2y^2+k = [3x^2+5xy] - [2x^2+xy]

=> 2y^2+k = 3x^2+5xy - 2x^2 - xy

=> 2y^2+k = x^2+4xy

or k = x^2-2y^2+4xy...