Math, asked by pranav1503, 9 months ago

what should be added to 2x^2-3x-8 to get 3x^3+x^2-13​

Answers

Answered by Cynefin
22

Answer:

Hey mate, Good morning ❤

#Here's ur answer...☆☆☆

Step-by-step explanation:

 \boxed{ \underline{ \huge{ \mathfrak{ \pink{ answer...}}}}}

to \: find  \\  \red{ \bold{\: 2 {x}^{2} - 3x - 8 + p(x) = 3 {x}^{3}   +  {x}^{2}  - 13}} \\ where \: p(x)should \: be \: added... \\ p(x) = 3 {x}^{3} +  {x}^{2} - 13 - (2 {x}^{2} - 3x - 8) \\  = 3 {x}^{3   }  +  {x}^{2}   - 13   - 2 {x}^{2} + 3x + 8 \\  = 3 {x}^{3}  - x {}^{2} + 3x - 5( \blue {answer})

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Answered by satheeshsrileka
0

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