Question

What should be added to (3/6+1/2+2/4) to get 1​

Answer 1

Answer:

Let the unknown number be = x

$\frac{3}{6} + \frac{1}{2} + \frac{2}{4} + x = 1 \\ \\ = lcm = 2 \times 2 \times 3 = 12 \\ \\ = \frac{6}{12} + \frac{6}{12} + \frac{6}{12} + 12x = 1 \\ \\ = \frac{18 + 12x}{12} = 1 \\ \\ = 18 + 12x = 12 \\ \\ = 12x = 12 - 18 \\ \\ = 12x = - 6 \\ \\ = x = \frac{ - 6}{12} \\ \\ = x = \frac{ - 1}{2}$

Required number -

$\frac{-1}{2}$

Answer 2

Step-by-step explanation:

Let the unknown number be = x

\begin{gathered} \frac{3}{6} + \frac{1}{2} + \frac{2}{4} + x = 1 \\ \\ = lcm = 2 \times 2 \times 3 = 12 \\ \\ = \frac{6}{12} + \frac{6}{12} + \frac{6}{12} + 12x = 1 \\ \\ = \frac{18 + 12x}{12} = 1 \\ \\ = 18 + 12x = 12 \\ \\ = 12x = 12 - 18 \\ \\ = 12x = - 6 \\ \\ = x = \frac{ - 6}{12} \\ \\ = x = \frac{ - 1}{2} \end{gathered}