Question

what should be added to -3/9 to get 1.
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Answer 1

Answer:

We will get $\frac{4}{3} +\frac{-3}{9} =1.$

Step-by-step explanation:

• We have to evaluate the above expression by using the given data.

         Given data:- $x+\frac{-3}{9}=1.$

         To find:- Value of the missing term.

        Solution:-

• Let assume x to find the missing term.

• Then the result will be the solution for the given linear equation.

• By using the transposition method.

        we get,

         $x+\frac{-3}{9}=1\\=>x-\frac{1}{3}=1\\ =>x= 1+\frac{1}{3}\\=>x=\frac{4}{3}$

        We will get the missing term is $\frac{4}{3} .$

Answer 2

Answer:

$\frac{4}{3}$ should be added to $\frac{-3}{9}$ to get $1$.

Step-by-step explanation:

In context to question given,

• We have to find the number that should be added to $\frac{-3}{9}$ to get $1$.
• Let, $x$ be the number which is added to $\frac{-3}{9}$ to get $1$.
• The required equation becomes,

       $x+(-\frac{3}{9} )=1$

        ∴ $x-\frac{3}{9} =1$

• By cross multiplication, we get

        ∴ $\frac{9x-3}{9} =1$

        ∴ $9x-3=9$

             ∴ $9x=9+3$

              ∴ $9x=12$

              ∴ $x=\frac{12}{9}$

              ∴ $x=\frac{4}{3}$

• ∴ $\frac{4}{3}$ should be added to $\frac{-3}{9}$ to get $1$.