Question

what should be added to -3a+7b -16 to get the sum -8?

Answer 1

-8 - (3a + 7b - 16)
= - 8 + 3a - 7b + 16
= 3a - 7b + 16 - 8
= 3a - 7b + 8

Therefore, 3a - 7b + 8 should be added to - 3a + 7b - 16 to get the sum - 8.

Hope it'll help....:)

Answer 2

The answer is 3a+7b+8

GIVEN

Number: -3a+7b -16

Resultant after addition = -8

TO FIND

We can simply solve the above problem as follows;

It is given

A number - -3a+7b-16

We need to another number such that the resultant number is -8.

We can observe that the resultant does not have variables, This means that the the variables were cancelled during addition.

This is only possible when the the variable are added with same numbers with opposite sign.

Given number- -3a+7b-16

Let the number to be added be x

therefore,

-3a+7b - 16 + x = -8

Bringing 3a+7b - 16 to RHS;

x = -8 +3a -7b + 16

x = +3a-7b+16-8

x = 3a+7b+8

Hence, The answer is 3a+7b+8

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