What should be added to 3m²-5 n² to get 4m^2+2n^2+3mn
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Using the identity:(x+y)2=x2+y2+2xy.
We have: (3m+5n)2−(2n)2 and apply the above identity as follows:
(3m+5n)2−(2n)2=[(3m)2+(5n)2+(2×3m×5n)]−4n2=9m2+25n2+30mn−4n2=9m2+21n2+30mn
=3(3m2+7n2+10mn)
Hence, (3m+5n)2−(2n)2=3(3m
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