Question

What should be added to 3x2 + xy + 3y2 to
obtain 4x2 + 6xy ?
(1) x2 + 5xy - 3y2
(2) x2 – 5xy - 3y2
(3) x2 + 5xy +3y2
(4) x2 +6xy - 3y2


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Answer 1

Answer:

$lets \: put \: x$

$\underline\mathfrak\blue{give;-}$

$(x) + ( {3x}^{2} + xy + {3y}^{2} = {4x}^{2} + 6xy$

$x = ({3x}^{2} + xy + {3y}^{2}) - ( {4x}^{2} + 6xy)$

$x = {x}^{2} + 5xy + {3y}^{2}$

so if we will add x²+5xy+3y² to 3x² + xy + 3y²

we, will got 4x²+6xy

hence, x²+5xy+3y² will added.

Answer 2

Answer:

Answer:

lets \: put \: xletsputx

\underline\mathfrak\blue{give;-}

give;−

(x) + ( {3x}^{2} + xy + {3y}^{2} = {4x}^{2} + 6xy(x)+(3x

2

+xy+3y

2

=4x

2

+6xy

x = ({3x}^{2} + xy + {3y}^{2}) - ( {4x}^{2} + 6xy)x=(3x

2

+xy+3y

2

)−(4x

2

+6xy)

x = {x}^{2} + 5xy + {3y}^{2}x=x

2

+5xy+3y

2

so if we will add x²+5xy+3y² to 3x² + xy + 3y²

we, will got 4x²+6xy

hence, x²+5xy+3y² will added.