Math, asked by balkarsingh980082, 10 months ago

what should be added to 3xy-4yz+4zz to get zy±3yz-2zx+7​

Answers

Answered by komalsingh59
1

Step-by-step explanation:

3xy - 4yz + 4zz - zy + 3yz - 2zx + 7 =

3xy - yz + 4zz - 2zx + 7 is the right answer...

Answered by Aryansraut12
0

Req. number =zy +3yz -2xz +7 -(3xy-4yz+4xz)

=zy+3yz-2xz+7-3xy+4yz-4xz

=8yz-6xz-3xy +7

or 6yz-6xz-3xy+7

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