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What should be added to 3y2 – 4x - 3x2 – 5 to obtain x2 – 2y + 6?
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Hey frand here is your answer
Given : -3x² + 3y² - 4x -5 (= p, let)
To obtain : x² - 2y + 6 (= q, let)
We just need to subtract q from p
therefore p - q
= -3x² + 3y² - 4x -5 - (x² - 2y + 6)
= -3x² + 3y² - 4x -5 - x² + 2y - 6
= (-3x² - x²) + 3y² - 4x + 2y + (-5 - 6)
= - 4x² + 3y² - 4x + 2y - 11
this is what you actually need to add....
I hope it may help you....!!!
Thanks
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