what should be added to 4c(-a+b+c) to obtain 3a(a+b+c)-2b(a+b+c)-2b(a-b+c)?
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Step-by-step explanation:
to find the unknown expression we have to subtract 3a(a+b+c)-2b(a+b+c)-2b(a-b+c) from 4c(-a+b+c)
=4c(-a+b+c) - [ 3a(a+b+c) -2b(a+b+c) -2b(a-b+c) ]
= -4ac + 4bc + 4c² - ( 3a²+3ab+3ac -2ab-2b²-2bc -2ab+2b²-2bc )
= -4ac + 4bc + 4c² - ( 3a²-ab+3ac-4bc )
= -4ac + 4bc + 4c² -3a²+ab-3ac+4bc
= -7ac +8bc +4c² -3a² +ab
= -3a²+ab+8bc-7ac+4c² ANS
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