What should be added to 4x3-10x2+12x+6 so that it becomes exactly divisible by 2x +1
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4x^3–10x^2+12x+6 divided by (2x+1) gives a quotient of (2x^2–6x+9) and a remainder of -3. So you need to add 3 to the dividend to make it 4x^3–10x^2+12x+9.
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Answer:
4*3-10*2+12*+6-2*1 do this u can get the answer
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