What should be added to 6.387 to get 10
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Let the number be ‘x’ \therefore\frac{-3}{16}+x\ =\ \frac{11}{24}x=\frac{11}{24}-\frac{-3}{16}x=\ \frac{11\times2}{24\times2}-\frac{\left(-3\times3\right)}{16\times3}x=\ \frac{22}{48}-\frac{-9}{48}x=\frac{22-\left(-9\right)}{48}=\frac{22+9}{48}=\frac{31}{48}
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Answer:
3.613
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