Question

What should be added to 6a² - 4ab + b2 to get 9a² + 2ab - 62?​

Answer 1

Step-by-step explanation:

simply subtract 6a²-4ab+b² from 9a²+2ab-62

so the answer is

9a²+2ab-62-6a²+4ab+b²

=3a²+8ab-62-6a²

Answer 2

GIVEN :

Sum of two numbers = 9a² + 2ab - 62

First number = 6a² - 4ab + b²

TO FIND :

OTHER NUMBER WHICH IS ADDED TO 6a² - 4ab + b² TO GET 9a² + 2ab - 62

SOLUTION :

let the other number be X

ATQ=>

X + 6a² - 4ab + b² = 9a² + 2ab - 62

X = 9a² + 2ab - 62 - (6a² - 4ab + b²)

X= 9a² + 2ab - 62 -6a² + 4ab - b²

x= 9a² -6a² + 2ab + 4ab -62-b²

x= 3a² +6ab -62-b²

ANSWER :

3a² +6ab -62-b² should be added to 6a² - 4ab + b2 to get 9a² + 2ab - 62..

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