Question

What should be added to 7 1/3 to get 21?

Answer 1

$\huge\bf{\underline{\red{Solution:-}}}$

Let the number be y

• Now

• y is added to$\sf 7\dfrac{1}{3}$ to get 21

Now

$\bf\underline{\red{According\:To\: Question:-}}$

$\sf\implies 7\dfrac{1}{3}+y=\:\:21\\ \\ \sf\implies \dfrac{22}{3}+y=\:\:21\\ \\ \sf\implies y=21-\dfrac{22}{3}\\ \\ \sf\implies y= \dfrac{21\times 3-22}{3}\\ \\ \sf\implies y= \dfrac{63-22}{3}\\ \\ \sf\implies y= \dfrac{41}{3}\\ \\ \sf\:\:\:or\:\:y= 13\dfrac{2}{3}$

• So the number is

$\boxed{\sf{\red{13\dfrac{2}{3}}}}$

Answer 2

Let no. be 'x'

According to question:-

$\mathbf \red{ 7\frac{1}{3} + x = 21}$

$\mathbf \red{\frac{22}{3} - 21 = x}$

$\bf \red{ \frac{63-22}{3} = x}$

$\bf \red{ \frac{41}{3} = x}$

$\bf \red{x = 13 \frac2{3}{} }$