Question

what should be added to -7/8 so as to get 5/9?​

Answer 1

➤ Answer :-

$\tt \to \dfrac{( - 7)}{8} + ( \sf x) \tt = \dfrac{5}{9}$

To find 'x' in the following sum, we should subtract $\tt\dfrac{(-7)}{8}$ from $\tt\dfrac{5}{9}$

$\sf \to(x) \tt = \dfrac{5}{9} - \dfrac{( - 7)}{8}$

Convert them into like fractions.......

LCM of 9 and 8 is 72.

$\tt \to \dfrac{5 \times 8}{9 \times 8} - \dfrac{( - 7) \times 9}{8 \times 9}$

$\tt \to \dfrac{40}{72} - \dfrac{( - 63)}{72} = \dfrac{40 - ( - 63)}{72}$

$\tt \to \dfrac{( - 103)}{72} = -1 \dfrac{31}{72}$

$\Huge\therefore$The other number is $\tt - 1 \dfrac{31}{72}$