Question

What should be added to _8/9 To get 2/5​

Answer 1

Given :

• Sum of two numbers = 2/5
• Given Number = 8/9

To Find :

• Second Number.

Solution :

$\longmapsto\tt{Let\:other\:no.\:be=x}$

A.T.Q :

$\longmapsto\tt{\dfrac{8}{9}+x=\dfrac{2}{5}}$

$\longmapsto\tt{x=\dfrac{2}{5}-\dfrac{8}{9}}$

$\longmapsto\tt{x=\dfrac{18-40}{45}}$

$\longmapsto\tt\bold{x=\dfrac{-22}{45}}$

So , The second number is -22/45...

_______________________

VERIFICATION :

$\longmapsto\tt{\dfrac{8}{9}+\dfrac{(-22)}{45}=\dfrac{2}{5}}$

$\longmapsto\tt{\dfrac{8}{9}-\dfrac{22}{45}=\dfrac{2}{5}}$

$\longmapsto\tt{\dfrac{40-22}{45}=\dfrac{2}{5}}$

$\longmapsto\tt{\cancel\dfrac{18}{45}=\dfrac{2}{5}}$

$\longmapsto\tt\bold{\dfrac{2}{5}=\dfrac{2}{5}}$

HENCE VERIFIED

Answer 2

Given :

Sum of two numbers = 2/5

Given Number = 8/9

To Find :

Second Number.

Solution :

\longmapsto\tt{Let\:other\:no.\:be=x}⟼Letotherno.be=x

A.T.Q :

$\longmapsto\tt{\dfrac{8}{9}+x=\dfrac{2}{5}}$⟼

9\8

+x=

5\2

$\longmapsto\tt{x=\dfrac{2}{5}-\dfrac{8}{9}}$⟼x=

5\2

−

9\8

$\longmapsto\tt{x=\dfrac{18-40}{45}}$⟼x=

45

18−40

\longmapsto\tt\bold{x=\dfrac{-22}{45}}⟼x=

45\−22

So , The second number is -22/45...

_______________________

VERIFICATION :

\longmapsto\tt{\dfrac{8}{9}+\dfrac{(-22)}{45}=\dfrac{2}{5}}⟼

9\8

+

45(−22=

52