Math, asked by ks817097, 2 months ago

What should be added to 9=2/3 to get 19​

Answers

Answered by nd332346
1

Answer:

y=9 1/3

PREMISES

y=9 2/3+r=19

ASSUMPTIONS

Let r=the number added to 9 2/3 (addend)

CALCULATIONS

y=9 2/3+r=19

(9 2/3–9 2/3)+r=19–9 2/3

0+r=9 1/3

r=

9 1/3

PROOF

If r=9 1/3, then the equations

9 2/3+9 1/3=19 and

19=19 prove the root (zero) r=9 1/3 of the addition 9 2/3+r=19

C.H.

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Let me ask you two questions:

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What should we add to 10 to get 19 ?

I bet that you already know how to answer each of these questions. Add those numbers together and you will have the answer to your question.

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9 2/3 = 29/3

Add x = 29/3 to get 19, So x = 19 - 29/3 = (57–29)/3 = 28/3.

So add 28/3 or (9 and 1/3) to (9 and 2/3) to get 19.

Using the J programming language:

19 - 9+2r3

28r3

The answer is 28/3

Check:

28r3+ 9+2r3

19

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Subtraction of mixed numbers is most easily done by having common denominators.

19 - 9 2/3 = 57/3 - 29/3 = 28/3 = 9 1/3.

If you want another way, perhaps you can see a way of borrowing. 19 - 9 2/3 = 18 3/3- 9 2/3 = 9 1/3.

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“What should be added to x to get y” is practically the definition of y - x. In the present case 19 -9 2/3 = 9 1/3, so there’s your answer. 9 1/3 must be added to 9 2/3 to get 19.

I’m curious about what aspect of the problem had you stumped?

It will be 9 1/3

9 2/3 + 9 1/3

= 29/3 + 28/3

= 57/3

=19

Simple

9 2/3+(19–9 2/3)= 19

9 1/3

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Step-by-step explanation:

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