Question

What should be added to a2 – 3xy + b2 to obtain 3a2+ 11xy – 7b2?​

Answer 1

Answer:

let the no. be x

=(a^2-3xy+b^2)+ x =3a^2+11xy-7b^2

= x= (3a2+11xy-7b2) -(a2-3xy+b2)

=x = 2a^2+14xy-8b^2

Answer 2

Answer:

2a2 + 14xy - 8b2

Step-by-step explanation:

Let the unknown value be "x"

a2 – 3xy + b2 + x = 3a2+ 11xy – 7b2

x = (3a2 + 11xy - 7b2) - (a2 – 3xy + b2)

x = 2a2 + 14xy - 8b2