Question

what should be added to double the rational number 6/3 to get 5/7?​

Answer 1

Answer:

Suppose x be the rational number which is to be add.

According to the given condition,

2×3−7+x=73⟹3−14+x=73⟹x=73+314[Transposing3−14toRHS]⟹x=213×3+14×7=219+98⟹x=21107

Answer 2

Answer :-

• The required number is -23/7.

To find :-

• The number which should be added to double the rational number 6/3 to get 5/7.

Solution :-

• Before finding the required number, let's double the rational number 6/3!

$\rm \longrightarrow \dfrac{6}{3} \times 2$

$\rm \longrightarrow \dfrac{2}{1} \times 2$

$\rm\longrightarrow 2 \times 2$

$\rm \longrightarrow 4$

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• Now, let's find the number which should be added to 4 to get 5/7!

Let :-

• The required number be "x".

According to the question,

$\longmapsto \tt x + 4 = \dfrac{5}{7}$

$\tt\longmapsto x = \dfrac{5}{7} - 4$

$\tt \longmapsto x = \dfrac{(5 \times 1) - (4 \times 7)}{7}$

$\tt\longmapsto x = \dfrac{5 - 28}{7}$

$\tt \longmapsto x = \dfrac{ - 23}{ \: \: \: \: 7}$

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Verification :-

• To check our answer, let's add 4 and -23/7 and see whether we get 5/7!

$\dashrightarrow \sf4 + \dfrac{ - 23}{ \: \: \: \: 7}$

$\dashrightarrow \sf\dfrac{4}{1} + \dfrac{ - 23}{ \: \: \: \: 7}$

$\dashrightarrow \sf \dfrac{(4 \times 7) + ( - 23 \times 1)}{7}$

$\dashrightarrow \sf \dfrac{28 - 23}{7}$

$\dashrightarrow \sf \dfrac{5}{7}$

We get 5/7 on adding 4 and -23/7.

Hence verified!

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