Question

What should be added to each term of the ratio 5 : 11, so that the ratio becomes 3 : 4? ​

Answer 1

Answer:

x = 13/2

Step-by-step explanation:

5+x : 11+x :: 3 : 4

5+x/11+x = 3/4

4(5+x) = 3(11+x)

20+x = 33+x

x+x = 33-20

2x = 13

x = 13/2

Answer 2

$\underline{ \underline{ \sf \maltese\:{Given:-}}}$

• First ratio = 5:11
• Second ratio = 3:4

$\underline{ \underline{ \sf \maltese \:{To \: find:-}}}$

• The number that should be added to each term of the first ratio to turn it into the second ratio.

$\underline{ \underline{ \sf \maltese \:{Solution:-}}}$

Let:-

• The required number = x

By the problem:-

$\rm\dfrac{5 + x}{11+x} = \dfrac{3}{4}$

⇒ 4(5 + x) = 3(11 +x)

⇒ 20 + 4x = 33 + 3x

⇒ 4x - 3x = 33 - 20

⇒ x = 13

•°• the number that should be added is 13