What should be added to polynomial ³ – 3² – 15 + 6 , so that it is completely divisible by ( – 3 )
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Answer:
-3
Step-by-step explanation:
Concept:
The remainder when f(x) is divided by (x-a)
is f(a)
Let f(x)= x³-3x² +6x-15
The remainder when f(x) is divided by (x-3)
=f(3)
=(3)³-3(3)² +6(3)-15
=27-27+18-15
=3
Therefore -3 should be added so that it is exactly divisible by (x-3)
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