Question

What should be added to
$2 \frac{3}{5}$
To get
$4 \frac{2}{1}$
​

Answer 1

Answer:

$\frac{17}{5}$

please refer to the attachment for further information about this question.

Answer 2

$\red{\dag}\underline{\underline{\textsf{\textbf{ Solution\::- }}}}$

$\dashrightarrow\qquad\sf Let \: the \: first \:number \:be \:x.$

$\dashrightarrow\qquad\sf 2nd \:number = 2 \dfrac{3}{5}$

$\dashrightarrow\qquad\sf According \: to \: question,$

$\dashrightarrow\qquad\sf x + 2\dfrac{3}{5} = 4\dfrac{2}{1}$

$\dashrightarrow\qquad\sf x + \dfrac{13}{5} = \dfrac{6}{1}$

$\dashrightarrow\qquad\sf x = \dfrac{6}{1} - \dfrac{13}{5}$

$\dashrightarrow\qquad\sf x = \dfrac{6 \times 5 - 13 \times 1 }{5}$

$\dashrightarrow\qquad\sf x = \dfrac{30 - 13}{5}$

$\dashrightarrow\qquad\sf x = \dfrac{17}{5}$

$\red{\dag}\underline{\underline{\textsf{\textbf{ Therefore,\::- }}}}$

$\large\sf\red {The \:required\: number \:is \: \dfrac{17}{5} }$

$\red{\dag}\underline{\underline{\textsf{\textbf{ Verification \::- }}}}$

$\dashrightarrow\qquad\sf \dfrac{17}{5} + \dfrac{13}{5} = \dfrac{6}{1}$

$\dashrightarrow\qquad\sf \dfrac{30}{5}= \dfrac{6}{1}$

$\dashrightarrow\qquad\sf \dfrac{6}{1}= \dfrac{6}{1}$

$\dashrightarrow\qquad\sf LHS = RHS$

$\dashrightarrow\qquad\sf Hence \: verified$