Question

what should be added to the polynomial 3 X raised to 4 minus 4 x cube minus 6 X square + 4 so that it is completely divisible by x square - 2

Answer 1

The $8X-4$ must be added to the polynomial so that the polynomial

$3X^4-4X^3-6X^2+4$

Step-by-step explanation:

To calculate the value that should be added to polynomial $3x^4-4x^3-6x^2+4$ .we have to devide the polynimial by polynomial $x^2-2$

NOW      

                          $\frac{3x^4-4x^3-6x^2+4}{x^2-2}$

             $\frac{3x^2(3x^4-4x^3-6x^2+4)-4x(3x^4-4x^3-6x^2+4)-8x+4}{3x^4-4x^3-6x^2+4}$

        therefore the remainder is -8x+4

Therefore the remainder  must be subtracted from the polynomial so that is will be complytely divisble by $x^2-2$

     

HENCE THE YOUR ANSWER IS    

                               $=-(-8X+4)\\=8X-4$

                         

                         

Answer 2

Step-by-step explanation: