Question

what should be added to the polynomial x^2-5x^2+4 so that (x-3) is the factor of the resulting polynomial??????? ​

Answer 1

$p(x) = x { }^{2} - 5x {}^{2} + 4 \\ \\ g(x) = x - 3 \\ = x - 3 = 0 \\ = x = 3 \\ \\ let \:be \: add \: k \\ x { - 5x {}^{} }^{2} + 4 + k = 0 \\putting \: x = 3 \\ = (3) {}^{2} - 5 \times (3) { + 4 + }^{} k = 0 \\ = 9 - 5 \times 9 + 4 + k = 0 \\ = 9 - 45 + 4 + k = 0 \\ = 13 - 45 + k = 0 \\ = - 32 + k = 0 \\ = k = 32$

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Answer 2

Step-by-step explanation:

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