Question

What should be added to the polynomial x3 +9x2 +23x +10 so that it
becomes exactly divisible by (x+5)
​

Answer 1

Step-by-step explanation:

to make (X+5) divisible by p(X)

x +5 = 0

x = -5

put this vale in p(X)

(-5)^3 + 9(-5)^2 + 23(-5) + 10

-125 + 225 - 115 + 10

100 -105

-5

so if you subtract (-5) from given polynomial then it will be divisible by X + 5

Answer 2

Answer:

$(x {}^{3} + 9x {}^{2} + 23x + 10) \div (x + 5)$