Math, asked by nidhinsj, 7 months ago

what should be added to the sum of -1/3 and 3/5 to get the additive inverse of 2/3​

Answers

Answered by Prakhar8651
2

Answer:

-14/15

Step-by-step explanation:

let number be x

x+(3/5-1/3)=-(2/3)

x+(9-5/15)=-2/3

x+4/15=-2/3

x=-2/3-4/15

x=-10-4/15

x=-14/15

Answered by mohnishbansal310808
1

Answer:

-14/15

Step-by-step explanation:

additive inverse of 2/3 = (-2/3)

additive inverse of 2/3 = (-2/3)let the required no. be x

additive inverse of 2/3 = (-2/3)let the required no. be x-1/3 + 3/5 + x = (-2/3)

additive inverse of 2/3 = (-2/3)let the required no. be x-1/3 + 3/5 + x = (-2/3)x = (-2/3) + 1/3 - 3/5

additive inverse of 2/3 = (-2/3)let the required no. be x-1/3 + 3/5 + x = (-2/3)x = (-2/3) + 1/3 - 3/5x = (-10 + 5 - 9)/15

additive inverse of 2/3 = (-2/3)let the required no. be x-1/3 + 3/5 + x = (-2/3)x = (-2/3) + 1/3 - 3/5x = (-10 + 5 - 9)/15x = -14/15

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