what should be added to (x-4)(x+6) to get the product (x-3)(x-8)?
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Answered by
6
48 - 13x is added with (x-4)(x+6) to get the product (x-3)(x-8)
aarushi66:
send me whole process
(x-4)(x+6) + A = (x-3)(x-8)
let A be the value that is to be added
ok
expand (x-4)(x+6) and (x-3)(x-8)
then solve for A
tq
np
Answered by
19
here
(x-4)(x+6)=x^2+2x-24
(x-3)(x-8)=x^-11x+24
required term=-(x-3)(x-8)-(x-4)(x+6)
=x^2-11x+24-x^2-2x+24
=48-13x.......ans
(x-4)(x+6)=x^2+2x-24
(x-3)(x-8)=x^-11x+24
required term=-(x-3)(x-8)-(x-4)(x+6)
=x^2-11x+24-x^2-2x+24
=48-13x.......ans
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