What should be added to x2-3xy+4y2 to get 2x2+7xy-3y2
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Answer:
the other number is x^2+10xy-7y^2
Step-by-step explanation:
let a be the number
a + (x^2-3xy+4y^2) = 2x^2+7xy-3y^2
a = (2x^2+7xy-3y^2) - (x^2-3xy+4y^2)
a = 2x^2+7xy-3y^2-x^2+3xy-4y^2
a = 2x^2-x^2+7xy+3xy-3y^2-4y^2
a = x^2+10xy-7y^2
The other number is x^2+10xy-7y^2
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