what should be added to x3 -5x2+x-8 ,so that the result is exactly divisible by (x-5)
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Answered by
8
Answer:
when p (x) is divided by x-5 than remainder is -3 so -3 should be added
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jay09052004:
thanks bhaiy
Answered by
3
Answer:
-3
Step-by-step explanation:
x^3-5x^2 +x-8 /x-5
you wil get quotient x^ 2+1 with remainder 3
.hence you should add (-3) to x^3 -5x^2 +x-8 to make it exactly divisible by x-5.
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