Question

What should be added to xy – 3yz + 4zx to get 4xy – 3yz + 4yz + 7?

Answer 1

Answer:

Answer

AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression.

AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression.Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx)

AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression.Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx)= 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx.

AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression.Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx)= 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx.= 4xy – xy – 3zx – 4zx + 4yz + 3yz + 7.

AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression.Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx)= 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx.= 4xy – xy – 3zx – 4zx + 4yz + 3yz + 7.= 3xy – 7zx + 7yz + 7.

Answer 2

$\huge \sf \red{Answer}$

Let,

$\sf{The \: polynomial \: that \: should \: be \: added \: be \:  P}$

$\sf \pink{Then \: according \: to \: question,}$

$\sf{(xy−3yz+4zx)+P=(4xy−3zx+4yz+7)}$

$\sf{⇒P=(4xy−3zx+4yz+7)−(xy−3yz+4zx)}$

$\sf{⇒P=4xy−3zx+4yz+7−xy+3yz−4zx}$

$\sf \pink{Rearranging \: and \: collecting \: like \: terms,}$

$\sf{⇒P=4xy−xy−3zx−4zx+4yz+3yz+7}$

$\sf{⇒P=3xy−7zx+7yz+7}$

$\sf \pink{Hence, 3xy−7zx+7yz+7 should \: be \: added \: to \: get \: the \: required \: result.</p><p></p><p></p><p>}$

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