Math, asked by Dnyaneshwari118, 2 months ago

What should be added to xy – 3yz + 4zx to get 4xy

– 3zx + 4yz + 7?

This is class 7 question what should be the answer to it in steps?​

Answers

Answered by rajbirsangwan27
4

Answer:

AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression. AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression. Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx)= 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx.

Answered by therudreshbokade
0

Answer:

3xy+7yz-7zx+7

Step-by-step explanation:

something is added xy-3yz+4zx to get 4xy-3zx+4yz+7.

therefore,

something + (xy-3yz+4zx) = 4xy+4yz-3zx+7

something = 4xy+4yz-3zx+7 - (xy-3yz+4zx)

something = 4xy+4yz-3zx+7-xy+3yz-4zx

something = 4xy-xy+4yz+3yz-3zx-4zx+7

something = 3xy+7yz-7zx+7

i.e. the answer is 3xy+7yz-7zx+7

I HOPE IT WILL HELP YOU!

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