What should be added to xy – 3yz + 4zx to get 4xy
– 3zx + 4yz + 7?
This is class 7 question what should be the answer to it in steps?
Answers
Answered by
4
Answer:
AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression. AnswerBy subtracting xy – 3yz + 4zx from 4xy – 3zx + 4yz + 7, we get the required expression. Therefore, required expression = (4xy – 3zx + 4yz + 7) – (xy – 3yz + 4zx)= 4xy – 3zx + 4yz + 7 – xy + 3yz – 4zx.
Answered by
0
Answer:
3xy+7yz-7zx+7
Step-by-step explanation:
something is added xy-3yz+4zx to get 4xy-3zx+4yz+7.
therefore,
something + (xy-3yz+4zx) = 4xy+4yz-3zx+7
something = 4xy+4yz-3zx+7 - (xy-3yz+4zx)
something = 4xy+4yz-3zx+7-xy+3yz-4zx
something = 4xy-xy+4yz+3yz-3zx-4zx+7
something = 3xy+7yz-7zx+7
i.e. the answer is 3xy+7yz-7zx+7
I HOPE IT WILL HELP YOU!
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