Question

what should be addedto 51/8 to get 10​

Answer 1

Hey there! Here is your answer.

Let required no be x

$\frac{51}{8} + x = 10 \\ = > x = 10 - \frac{51}{8} \\ = > x = \frac{80 - 51}{8} \\ => x = \frac{29}{8} \\ = > x = 3 \frac{5}{8}$
Hence, the no required is
$3 \frac{5}{8}$
Hope this answer will help you!

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Answer 2

HEY MATE

$\huge\mathfrak\red{Solution}$

$10 - \frac{51}{8} = \frac{80 - 51}{8} = \frac{29}{8} = 3.625$

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