Question

What should be sabtracted from -2/3 to get 3/4

Answer 1

Let the no. be x

$x - \dfrac{-2}{3} = \dfrac{3}{4}$

$x+ \dfrac{2}{3}= \dfrac{3}{4}$

$x = \dfrac{3}{4}- \dfrac{2}{3}$

[Take lcm,... Lcm = 12]

$x = \dfrac{3 \times 3 - 4 \times 2}{12}$

$x = \dfrac{9-8}{12}$

$x = \dfrac{1}{12}$

The no. is $\dfrac{1}{12}$

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Verify:-

$\dfrac{1}{12} - (\dfrac{-2}{3})$$\dfrac{1}{12}+ \dfrac{2}{3}$

LCM = 12

=$\dfrac{1+8}{12}$

=$\dfrac{9}{12}$

Both are divisible by 3.

=$(3 \times 3 = 9)$

=$(4 \times 3 = 12)$

=$\dfrac{3}{4}$

Hence proved...

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Additional Information

Signs are changed on the following bases:-

(+) (+) = +

(-) (-) = +

(+) (-) = -

(-) (+) = -