Question

what should be substracted from (3/4 - 1/3) to get (-1/4)​

Answer 1

hope it will help you

thank you

Answer 2

★ How to do :-

Here, we are given that two fractions should be subtracted by each other. We are said that, if we subtract the given numbers together we will obtain with the first fraction that the second fraction is to be subtracted with. We are also given with the answer obtained while subtracting those two fractions. But, we aren't given with any hint or the value of the second number that the first number should be subtracted with. We are also asked to find the same. We can find the answer of this question by a concept called as the transposition method. In this method, we shift the fractions from one hand side to the other. By this method, the sign of the appropriate number or fraction changes. So, let's solve!!

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➤ Solution :-

${\sf \leadsto \bigg( \dfrac{3}{4} - \dfrac{1}{3} \bigg) - y = \dfrac{(-1)}{4}}$

LCM of 4 and 3 is 12.

${\sf \leadsto \bigg( \dfrac{3 \times 3}{4 \times 3} - \dfrac{1 \times 4}{3 \times 4} \bigg) - y = \dfrac{(-1)}{4}}$

Multiply the numerators and denominators of both fractions.

${\sf \leadsto \bigg( \dfrac{9}{12} - \dfrac{4}{12} \bigg) - y = \dfrac{(-1)}{4}}$

Subtract the numbers in the bracket.

${\sf \leadsto \dfrac{5}{12} - y = \dfrac{(-1)}{4}}$

Shift the number on LHS to RHS, changing it's sign.

${\sf \leadsto y = \dfrac{5}{12} - \dfrac{(-1)}{4}}$

LCM of 4 and 12 is 12.

${\sf \leadsto y = \dfrac{5}{12} - \dfrac{(-1) \times 3}{4 \times 3}}$

Multiply the numerators and denominators of second fraction.

${\sf \leadsto y = \dfrac{5}{12} - \dfrac{(-3)}{12}}$

Subtract the fractions.

${\sf \leadsto y = \cancel \dfrac{8}{12} = \dfrac{2}{4}}$

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${\red{\underline{\boxed{\bf So, \: the \: other \: number \: is \: \dfrac{2}{3}.}}}}$

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Verification :-

${\sf \leadsto \dfrac{5}{12} - y = \dfrac{(-1)}{4}}$

Substitute the value of y.

${\sf \leadsto \dfrac{5}{12} - \dfrac{2}{3} = \dfrac{(-1)}{4}}$

LCM of 12 and 3 is 12.

${\sf \leadsto \dfrac{5}{12} - \dfrac{2 \times 4}{3 \times 4} = \dfrac{(-1)}{4}}$

Multiply the numerators and denominators of second fraction.

${\sf \leadsto \dfrac{5}{12} - \dfrac{8}{12} = \dfrac{(-1)}{4}}$

Subtract the fractions.

${\sf \leadsto \dfrac{(-3)}{12} = \dfrac{(-1)}{4}}$

Write the fraction in lowest form.

${\sf \leadsto \dfrac{(-1)}{4} = \dfrac{(-1)}{4}}$

So,

${\sf \leadsto LHS = RHS}$

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Hence verified !!