Question

what should be substracted from p^3-19pq-7q^2 to get 6p^3-4pq^2​

Answer 1

Answer:

Since on dividing p

2

- 6p + 7 by p -1 the remainder is 2. Hence if 2 is subtracted from p

2

- 6p + 7 then p

2

- 6p + 7 - 2 i.e., p

2

- 6p + 5 will be exactly divisible by p -1.