what should be substracted from p^3-19pq-7q^2 to get 6p^3-4pq^2
Answers
Answered by
1
Answer:
Since on dividing p
2
- 6p + 7 by p -1 the remainder is 2. Hence if 2 is subtracted from p
2
- 6p + 7 then p
2
- 6p + 7 - 2 i.e., p
2
- 6p + 5 will be exactly divisible by p -1.
Similar questions