What should be subtracted from 27x^2-9x^2-6x-5 to make it exactly divisible by 3x-1?
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27x^2-9x^2-6x-5 divide by 3x-1
and remainder is -5
5 is subtract from the polynomial
and remainder is -5
5 is subtract from the polynomial
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-5 should be substrated from that to make it divisible by 3x-1
Hope you are satisfied with my answer
Here's your answer looking for
Check it out in image
-5 should be substrated from that to make it divisible by 3x-1
Hope you are satisfied with my answer
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