Question

what should be subtracted from 2p2 + 3q2 + 6pq to get p2 - q2

Answer 1

see the photo for your answer

Answer 2

$\mathbb{\pink{\huge{Hello\:Mate!!!}}}$

$<b>Answer</b>$

$-p^2 + 2p^2 -6pq$

$<b>Step-by-step explanation</b>$

$(p^2-q^2) - (2p^2 + 3q^2 + 6pq)$

$(p^2-q^2) -2p^2 - 3p^2 - 6pq$

$(p^2 -2p^2) + (q^2 -3q^2) -6pq$

$-p^2 -2q^2 -6pq$


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