What should be subtracted from 2x³-3x²y+2xy² + 3y³ to get
x³ - 2x²y+3xy²+4y³ ?
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Answer:
2x³-3x²y+3xy²+3y³-(x³-2x²y+3xy²+4y³)
=2x³-3x²y+3xy²+3y³-x³+2x²y-3xy²-4y³
=x³-xy²-y³
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