What should be subtracted from -3/4 to get 5/6 ?
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Answer:
What should be subtracted from -3/4 to get 5/6 ?
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ANSWER: (−19/12)
STEP BY STEP EXPLANATION:
Let the missing number be x, then
Let the missing number be x, then(−3/4)−(x)=(5/6)
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)⇒(−3/4)−(5/6)=x
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)⇒(−3/4)−(5/6)=xNow,
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)⇒(−3/4)−(5/6)=xNow,LCM of 4 and 6 is 12
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)⇒(−3/4)−(5/6)=xNow,LCM of 4 and 6 is 12⇒(−3×3)/(4×3)=(−9/12)
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)⇒(−3/4)−(5/6)=xNow,LCM of 4 and 6 is 12⇒(−3×3)/(4×3)=(−9/12)⇒(−5×2)/(6×2)=(−10/12)
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)⇒(−3/4)−(5/6)=xNow,LCM of 4 and 6 is 12⇒(−3×3)/(4×3)=(−9/12)⇒(−5×2)/(6×2)=(−10/12)Putting these in the equation, we get:
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)⇒(−3/4)−(5/6)=xNow,LCM of 4 and 6 is 12⇒(−3×3)/(4×3)=(−9/12)⇒(−5×2)/(6×2)=(−10/12)Putting these in the equation, we get:⇒x=(−9−10)/12
Let the missing number be x, then(−3/4)−(x)=(5/6)By transposing (−x) form the left hand side to the right side it becomes (x) and (5/6) form right hand side left hand side it becomes (−5/6)⇒(−3/4)−(5/6)=xNow,LCM of 4 and 6 is 12⇒(−3×3)/(4×3)=(−9/12)⇒(−5×2)/(6×2)=(−10/12)Putting these in the equation, we get:⇒x=(−9−10)/12⇒x=(−19/12)