Question

What should be subtracted from 30ab +12b +14a to get 12 ab – 14 c + 15b?

Answer 1

In order to find the answer you need to subtract 12ab - 14c + 15b from 30ab + 12b + 14a
That is = ( 30ab+12b+14a ) - ( 12ab-14c+15b )
= 30ab+12b+14a-12ab+14c-15b
= 18ab-3b+14a+14c

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Answer 2

Answer:

18ab-3b+14a+14c

Step-by-step explanation:

HERE IS YOUR ANSWER:

let the subracted eqn is θab+φb+εa+ρc

30ab+12b+14a-(θab+φb+εa+ρc)=12ab-14c+15b

30ab+12b+14a-θab-φb-εa-ρc=12ab-14c+15b

(30-θ)ab+(12-φ)b+(14-ε)a-ρc=12ab-14c+15b

comparing lhs and RHS

then we get

30-θ=12

-θ=12-30

θ=18

12-φ=15

-φ=15-12

φ=-3

14-ε=0

ε=14

-ρ=15

ρ=-15

securing their values in the assumed equation

18ab-3b+14a+14c