Math, asked by roychampa, 10 months ago

What should be subtracted from 3a² - 4b²+ 5ab to obtain - a²- b² + 6ab?​

Answers

Answered by ashwindarshan2007
0

Answer:

To get the answer we must add 3a² - 4b²+ 5a with  - a²- b² + 6ab

Hence  3a² - 4b²+ 5ab + - a²- b² + 6ab = 2a^{2} + 11ab - 5b^{2}

So 2a^{2} + 11ab - 5b^{2} should be subtracted from 3a² - 4b²+ 5a to get - a²- b² + 6ab

Hope it helps

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