Question

What should be subtracted from 4a²-7ab-5b²-2 to get 5a²-6ab-3b²+7

Answer 1

Answer:

Let X be subtracted from 3a2−6ab−3b2

Then,

3a2−6ab−3b2−1−X=4a2−7ab−4b2+1

x=3a2−6ab−3b2−1−(4a2−7ab−4b2+1)

x=3a2−6ab−3b2−1−4a2+7ab+4b2−1

x=−a2+ab+b2−2