Math, asked by Sheetalyadav8919, 9 months ago

What should be subtracted from 4p²-2pq-6q²-r+5 to get -p²+pq-8q²-2r+6

Answers

Answered by biswajit1584
8

Answer:

5p²-3pq+2q²+r-1

Step-by-step explanation:

To get the required equation we have to subtract the given equation with the equation -p²+pq-8q²-2r+6

4p²-2pq-6q²-r+5-(-p²+pq-8q²-2r+6)

after solving this we get ,

5p²-3pq+2q²+r-1

for check,

4p²-2pq-6q²-r+5-(5p²-3pq+2q²+r-1)

=4p²-2pq-6q²-r+5-5p²+3pq-2q²-r+1

= -p²+pq-8q²-2r+6

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Answered by kaiminthang
1

Answer:

-3p²-pq-2q²-r-1

Step-by-step explanation:

substract -p²+pq-2q²-2r-1 from 4p²-2pq-6q²-r-5

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