What should be subtracted from 4p²-2pq-6q²-r+5 to get -p²+pq-8q²-2r+6
Answers
Answered by
8
Answer:
5p²-3pq+2q²+r-1
Step-by-step explanation:
To get the required equation we have to subtract the given equation with the equation -p²+pq-8q²-2r+6
4p²-2pq-6q²-r+5-(-p²+pq-8q²-2r+6)
after solving this we get ,
5p²-3pq+2q²+r-1
for check,
4p²-2pq-6q²-r+5-(5p²-3pq+2q²+r-1)
=4p²-2pq-6q²-r+5-5p²+3pq-2q²-r+1
= -p²+pq-8q²-2r+6
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Answered by
1
Answer:
-3p²-pq-2q²-r-1
Step-by-step explanation:
substract -p²+pq-2q²-2r-1 from 4p²-2pq-6q²-r-5
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